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Indians’ 1B Carlos Santana to be All-Star starter

CLEVELAND — The Cleveland Indians’ Carlos Santana will be the first baseman starter in the 2019 MLB All-Star game.

Voting opened Wednesday at noon and ended at 4 p.m. Thursday. Starters for the 2019 MLB All-Star Game, which will be played in Cleveland on July 9, were announced on ESPN at 7 p.m.

There were eight finalists in the National League and nine in the American League, counting the designated hitter. The candidates for the vote were selected during the Primary, which wrapped on June 21.

Santana was the only Indians player on the ballot.

He claimed 49.2 percent of the vote ahead of New York Yankees’ Luke Voit (25.8 percent) and Minnesota Twins’ C.J. Cron (25.0 percent).

Entering the day, he had the best 2019 numbers among AL first baseman finalists leading in average (.290) home runs (18), on-base pct. (.411), slugging pct. (.541) and OPS (.951).

“I’m excited to represent Cleveland alongside the best in Major League Baseball,” said Santana said in a press release. “To be able to start in my first career All-Star Game, and to do it at home in front of our fans, means everything to me.”

Over his 10-year MLB career, Santana has never been named to an All-Star roster. He will be the first Cleveland Indians first baseman to start in an All-Star Game since Jim Thome did in 1999.

Santana will also represent the Indians in the Home Run Derby. The Tribe first baseman and designated hitter said he plans to bat left for the event. This season, he is is batting .291 with 17 home runs and 47 RBIs.

All-Star festivities run from July 5, starting with Play Ball Park at the Huntington Convention Center, and culminate with the Midsummer Classic on July 9 at Progressive Field

More on the 2019 MLB All-Star Game in Cleveland, here.

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