Indians rally for wild, 14-inning, 10-9 win over Astros

CLEVELAND, OH - MAY 27: Greg Allen #1 of the Cleveland Indians hits a walk-off solo home run to defeat the Houston Astros during the fourteenth inning at Progressive Field on May 27, 2018 in Cleveland, Ohio. The Indians defeated the Astros 10-9 in the 14th inning. (Photo by Jason Miller/Getty Images)

CLEVELAND (AP) — Rookie Greg Allen homered on Brad Peacock’s first pitch in the 14th inning, and the Cleveland Indians stunned the Houston Astros 10-9 on Sunday.

Allen’s first homer of the season landed in the seats in right and triggered a wild celebration for the Indians, who rallied twice to overcome another impressive performance for Jose Altuve.

Cleveland scored five runs in the ninth. Michael Brantley’s two-out RBI single off Hector Rondon tied it at 8.

CLEVELAND, OH – MAY 27: The Cleveland Indians celebrate after Greg Allen #1 hit a walk-off solo home run to defeat the Houston Astros 10-9 in the 14th inning at Progressive Field on May 27, 2018 in Cleveland, Ohio. (Photo by Jason Miller/Getty Images)

Evan Gattis’ two-out homer off Dan Otero (1-1) gave Houston a 9-8 lead in the 13th, but Yonder Alonso responded with a leadoff drive against Collin McHugh in the bottom half.

Peacock (1-2) got the loss on the only pitch he threw.

Houston wasted a stellar day for Altuve, who had four hits and drove in two runs. The reigning AL MVP had a streak of 10 consecutive hits, breaking his own club record, before he lined out to center in the ninth.

More on the Indians, here.