Dwyane Wade reaches agreement on deal with Cleveland Cavaliers, reports say

Dwyane Wade #3 of the Chicago Bulls looks on during the third quarter of Game Five of the Eastern Conference Quarterfinals against the Boston Celtics at TD Garden on April 26, 2017 in Boston, Massachusetts. (Photo by Maddie Meyer/Getty Images)

CLEVELAND, Ohio — Dwyane Wade has reportedly reached an agreement on a one-year deal with the Cleveland Cavaliers.

On Tuesday, ESPN’s Adrian Wojnarowski tweeted that Wade plans to sign with Cleveland once he clears waivers on Wednesday.

Earlier in the day, Wojnarowski said Wade was nearing a commitment to sign with the Cavaliers.

Wade is eligible to sign a one-year, $2.3 million contract.

Wade, a Chicago native, left Miami after 13 years with the Heat. In 2010, he was joined in South Beach by LeBron James and Chris Bosh. The Big Three went to four straight NBA Finals and won two.

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