SANDUSKY, Ohio — President Obama’s campaign has added a stop in Sandusky to his two-day, swing-state bus tour.
According to a press release from Obama’s campaign, the stop is scheduled for Thursday, July 5.
The stop will now be sandwiched between events in Maumee in the morning and Parma in the evening.
The Sandusky stop will be an Ice Cream Social and is anticipated to begin around 3:40 p.m. at Washington Park, located on Washington Street between Wayne St. and Columbus Ave.
Information on tickets for the event will be released by Obama’s camp later on Tuesday.
Yesterday it was announced that the President was coming to James Day Park in Parma on Thursday evening.
The event is scheduled to get underway around 7:15 p.m.
The trip is part of a two-day bus tour throughout northern Ohio and western Pennsylvania in honor of Independence Day and to celebrate the American worker, according to campaign officials.
During the stop, President Obama plans to talk to constituents about his efforts to boost the economy since his time in office.
The Parma event is free for all to attend, though a ticket is required to be admitted.
Tickets for the Parma event can be picked up on a first come, first served basis starting at 10 a.m. Tuesday at the Organizing for America Field Offices located at 5734 Ridge Road in Parma, and 13100 Shaker Square in Cleveland.
Stay with Fox 8 as more details become available.